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Looking for Class 11 Maths Exercise 7.2 solutions? You’re at the right place! This section offers detailed and step-by-step answers to all the questions from Exercise 7.2 of Chapter 7 – Permutations and Combinations. These solutions follow the latest NCERT curriculum and help students dive deeper into the concept of permutations, including problems involving arrangements with repetition and restrictions. Whether you’re practicing from the Class 11 Ch 7 Exercise 7.2 solutions, referring to the NCERT Exemplar Class 11 Maths, or revising the topic of Permutation and Combination Class 11, these solutions will make your preparation smooth and effective. Download or explore the NCERT Solutions for Class 11 Maths Chapter 7 and strengthen your understanding today!
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Exercise 7.2
1.
\(4!=4 \times 3 \times 2 \times 1=24\)
\(3!=3 \times 2 \times 1=6\)
\(4!-3!=24-6=18\)
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\(4!=1 \times 2 \times 3 \times 4=24\)
\(3!+4!=6+24=30\)
\(7!=1 \times 2 \times 3 \times 4 \times 5 \times 6 \times 7=5040\)
\(3!+4! \neq 7!\)
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\(=\frac{1}{6!}+\frac{1}{7 \times 6!}=\frac{x}{8 \times 7 \times 6!}\)
\(=\frac{1}{6!}\left\{1+\frac{1}{7}\right\}=\frac{x}{8 \times 7 \times 6!}\)
\(=1+\frac{1}{7}=\frac{x}{8 \times 7}\)
\(=\frac{8}{7}=\frac{x}{8 \times 7}\)
\(=x=\frac{8 \times 8 \times 7}{7}\)
\(=x=64\)
5.
\(\Rightarrow \frac{n!}{(n-r)!}=\frac{6!}{(6-2)!}=\frac{6!}{4!}=\frac{6 \times 5 \times 4!}{4!}=30\)
\(=\frac{n!}{(n-r)!}=\frac{9!}{(9-5)!}=\frac{9!}{4!}=\frac{9 \times 8 \times 7 \times 6 \times 5 \times 4!}{4!}=15120\)
