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Looking for NCERT Class 9 Maths Exercise 1.1 solutions? You’ve come to the right place! This section provides clear, step-by-step solutions for all the questions from Chapter 1 – Number Systems (Exercise 1.1), as per the latest NCERT syllabus. These solutions are designed to help you understand the concepts of rational and irrational numbers, their properties and how they are used in real-life situations. Whether you’re preparing for your exams or just strengthening your basics, these Class 9 Maths solutions will help you build a solid foundation in number systems. View or download the complete solutions now and boost your confidence in maths from the very first chapter!

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Exercise 1.1
So, we can represent 3 and 4 in terms of fractions as an example:
(Multiplying \(\&\) dividing by 8)
\(3=\frac{3 \times 8}{8}=\frac{24}{8}\)
\(4=\frac{4 \times 8}{8}=\frac{32}{8}\)
NOTE: We can multiply \(\&\) divide by other numbers as well.
We are multiplying and dividing at the same time because it is easier to write other fractions in between. The decimal numbers between 3 \(\&\) 4 can also be written for e.g. 3.1, 3.2, 3.3, etc.
Now, we can write the six rational numbers between 3 and 4 as:
\(\frac{25}{8}, \frac{26}{8}, \frac{27}{8}, \frac{28}{8}, \frac{29}{8}, \frac{30}{8}\)
Now let us try dividing with some other number.(Multiplying and dividing by 10 )
\(3=\frac{3 \times 10}{10}=\frac{30}{10}\)
\(4=\frac{4 \times 10}{10}=\frac{40}{10}\)
And now we can write the rational numbers between 3 and 4 as \( \frac{31}{10}, \frac{32}{10}, \frac{33}{10}, \frac{34}{10} \ldots \). and so on
So, you can take any number.
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Trick: To find "n" rational numbers between any two numbers, multiply \( \& \) divide both by "\( \mathrm{n}+1 \)".
Between \( \frac{3}{5} \) and \( \frac{4}{5} \) there exist infinite rational numbers \(\&\) we know that rational numbers are fractions, whole numbers and decimals.
Trick: To find "n" rational numbers between any two numbers, multiply \(\&\) divide both by "\( \mathrm{n}+1 \)".
Example: If we need to find 5 rational numbers between \( \frac{3}{5} \) and \( \frac{4}{5} \), we multiply and divide both the numbers by 6 to obtain the set of rational numbers.
\(\frac{3}{5}=\frac{3 \times 6}{5 \times 6}=\frac{18}{30}\)
\(\frac{4}{5}=\frac{4 \times 6}{5 \times 6}=\frac{24}{30}\)
Hence, five rational numbers between \( \frac{3}{5} \) and \( \frac{4}{5} \) are:
\(\frac{19}{30}, \frac{20}{30}, \frac{21}{30}, \frac{22}{30}, \frac{23}{30}\)
Now its not necessary to only multiply and divide by \( \mathrm{n}+1 \), you can do by any number
\(\frac{3}{5}=\frac{3 \times 10}{5 \times 10}=\frac{30}{50}\)
greater than n. For example if you multiply and divide by 10
\(\frac{4}{5}=\frac{4 \times 10}{5 \times 10}=\frac{40}{50}\)
So the rational numbers between 3 and 4 now will be
\(\frac{31}{50}, \frac{32}{50}, \frac{33}{50}, \frac{34}{50}, \frac{35}{50}, \frac{36}{50}, \frac{37}{50}\)
Hence, five rational numbers.
4. State whether the following statements are true or false. Give reasons for your answers.
Natural numbers are numbers starting from \(1,\) i.e \(1, 2, 3, 4, 5, 6, \ldots\ldots\) And whole numbers are numbers starting from \(0\). i.e, \( 0,1,2,3,4,5 \ldots\ldots\) And you can see that all natural numbers are within whole numbers.
Now integers are numbers that are both negative and positive and include zero also, i.e., \( \ldots\ldots -3,-2,-1,0,1,2,3,4,\ldots\ldots \)
And whole numbers are numbers starting from \(0\). i.e., \( 0,1,2,3,4,5\ldots\ldots\) And clearly, negative numbers are missing from whole numbers.
Therefore, Whole numbers does not contain all rational numbers.